Fix for multiple cursors

[ds1-e]

Hey, i've encountered a annoying issue.

I use:

showCursor(not isCursorShowing(), true)

For toggle on/off cursor. Code works well, when it's a single use, but whenever i use it 2 times at once (different GUIs), it causes that cursor enables when closing GUI, so to fix this i need to reconnect or mess up with toggling on/off cursor with console. So i am curious how i could fix it. Any ideas?

[savour]

It's totally expected, when you hide the gui at the first time, isCursorShowing will return false after, so when you execute the function again it will show the cursor, as simple as that:

not true = false

not false = true

So, it you only want to hide it, why checking for its visibility

 

showCursor(false, true)

 

[IIYAMA]

3 hours ago, majqq said:

Any ideas?

Are we talking about 1 resource or multiple ones? Because resource A can't disable the cursor for resource B.

GUI's do not have any influence on the cursor function.

[ds1-e]

2 hours ago, IIYAMA said:

Are we talking about 1 resource or multiple ones? Because resource A can't disable the cursor for resource B.

GUI's do not have any influence on the cursor function.

One resource.

2 hours ago, savour said:

It's totally expected, when you hide the gui at the first time, isCursorShowing will return false after, so when you execute the function again it will show the cursor, as simple as that:

not true = false

not false = true

So, it you only want to hide it, why checking for its visibility

 

showCursor(false, true)

 

Ye but this is not what i want. For example. 2 GUI's opened, i close 1st, cursor stays until i close 2nd.

[savour]

In this case, you need to check to see if any of the two windows are visible, for example:

showCursor(guiGetVisible(window1) or guiGetVisible(window2), true)

-- or you can make it shorter with oop
showCursor(window1.visible or window2.visible, true)