question [QUESTION] How can I use scripts in different folders in my resource?

[Kazafka]

This is the dumbest question I've ever asked on this forum, but I have problem even not only with this. So, how can I add scripts from different folders in my meta.xml?

And in these scripts, how can I load xml files from different folders, too? Any idea? If yes, please, show me example

I know, that I would use 

xml = xmlLoadFile("filename.xml")

But how to load xml in different folders? Same

<script src="script.Lua" type="server"/>

But how to tell MTA to load script from different folder?

Edited January 14, 2020 by VaporZ

[Bilal135]

<file src="folder/filename.xml"/>

xml = xmlLoadFile("folder/filename.xml")

 

Edited January 14, 2020 by Bilal135

[Kazafka]

1 minute ago, Bilal135 said:

<file src="folder/filename.xml"/>

 

didn't helped bro

[Bilal135]

What’s the error?

[Kazafka]

Tryin' to do something

Gimme a second...

[Patrick]

I think you can't do that, but you can export functions.

Wiki: https://wiki.multitheftauto.com/wiki/Call

 

Example:

-- CLIENT
function print_msg(msg)
	outputChatBox(msg)
end

<meta>
	<script src="client.Lua" type="client"/>
	<export function="print_msg" type="client"/>
</meta>

 

After it you can call this 'print_msg' function from other resources:

-- CLIENT
exports.FIRST_RESOURCE_NAME:print_msg("called from other resource")

 

[Kazafka]

2 minutes ago, stPatrick said:

I think you can't do that, but you can export functions.

Wiki: https://wiki.multitheftauto.com/wiki/Call

 

Example:

-- CLIENT
function print_msg(msg)
	outputChatBox(msg)
end

<meta>
	<script src="client.Lua" type="client"/>
	<export function="print_msg" type="client"/>
</meta>

 

After it you can call this 'print_msg' function from other resources:

-- CLIENT
exports.FIRST_RESOURCE_NAME:print_msg("called from other resource")

 

But, how do I load a xml file, wich is in another folder, from a script, that is in default resource folder?

[Bilal135]

Lol I thought you were trying to load a file from a different folder within the same script.

[Kazafka]

<meta>
	<!-- Blah blah blah (info) and this: -->
	
	<script src="cars.Lua" type="client"/>
	<script src="bank.Lua" type="client"/>
	<script src="fshop.Lua" type="server"/>
	<script src="gunshop.Lua" type="server"/>
	
	<file src="VaporCars/shops.xml"/>
	<file src="VaporCars/saved.xml"/>
	<file src="Bank/accounts.xml"/>
	<file src="Bank/atms.xml"/>
	<file src="Gunshop/prices.xml"/>
</meta>

This?

Is this possible?

Just now, Bilal135 said:

Lol I thought you were trying to load a file from a different folder within the same script.

Kinda.

[Patrick]

So, you want to load a xml file with xmlLoadFile from other resource?

Enter the full path, from the root resource folder. ( start path with : )

 

xmlLoadFile(":OTHER_RESOURCE_NAME/SUBFOLDER/file.xml")

 

Edited January 14, 2020 by stPatrick

[Bilal135]

Probably create an export function that returns the desired xml file.

@stPatrick oh I didn’t know that was even possible

Edited January 14, 2020 by Bilal135

[Kazafka]

8 minutes ago, stPatrick said:

So, you want to load a xml file with xmlLoadFile from other resource?

Enter the full path, from the root resource folder. ( start path with : )

 

xmlLoadFile(":OTHER_RESOURCE_NAME/SUBFOLDER/file.xml")

 

NAAAH!

I want to load xml file in subfolder, but with script, that is in the same folder, as meta.xml!

Aaaaand this:

xml = xmlLoadFile("VaporCars/saved.xml")

Doesn't work!

"[...] Now you know!" ~ BELL BIV DEVOE - Poison

Edited January 14, 2020 by VaporZ

[Bilal135]

If you have added that in meta.xml, what does the debugscript output?

[Kazafka]

16 minutes ago, Bilal135 said:

If you have added that in meta.xml, what does the debugscript output?

Moving into another topic

[Felix5k]

try loadstring 

[Kazafka]

1 minute ago, Felix5k said:

try loadstring 

Another topic. More subfolder stuff, I guess.

[MIKI785]

Is it server or client? If it's on the server, there is no need to declare the files in meta.xml for it to work. However, the resource that does the loading needs access to the general.ModifyOtherObjects permission to be able to read files located in other resources.

[Bilal135]

1 hour ago, MIKI785 said:

Is it server or client? If it's on the server, there is no need to declare the files in meta.xml for it to work. However, the resource that does the loading needs access to the general.ModifyOtherObjects permission to be able to read files located in other resources.

His problem was solved in this topic.