Boolean with number

[Drakath]

Can someone tell me why do I get this error:

ERROR: rotation_check\server.lua:6: attempt to compare number with boolean

local x, y, z = getElementPosition(thePlayer) 
local px, py, pz = getElementPosition(ped) 
local rx,ry,rz = getElementRotation( ped ) 
local formula = tonumber((360 - math.deg(math.atan2((x - px), (y - py)))) % 360)+1 
if rz and formula then 
if not tonumber(rz) > tonumber(formula) then 
outputChatBox("Looking", root) 
else 
outputChatBox("Not looking", root) 
end 
end 

thePlayer and ped do exist.

[WhoAmI]

local x, y, z = getElementPosition(thePlayer) 
local px, py, pz = getElementPosition(ped) 
local rx,ry,rz = getElementRotation( ped ) 
local formula = tonumber((360 - math.deg(math.atan2((x - px), (y - py)))) % 360)+1 
outputChatBox ( type ( rz ) .. type ( formula ) ) 
if rz and formula then 
if not tonumber(rz) > tonumber(formula) then 
outputChatBox("Looking", root) 
else 
outputChatBox("Not looking", root) 
end 
end 

Check what it outptuts on chatbox.

[Drakath]

It outputs "numbernumber"

[Castillo]

if not tonumber(rz) > tonumber(formula) then 

The error is because when you do this: not tonumber(rz), you are converting it to a boolean.

You need to use parentheses, like this:

if not ( tonumber ( rz ) > tonumber ( formula ) ) then 

[Drakath]

if not tonumber(rz) > tonumber(formula) then 

The error is because when you do this: not tonumber(rz), you are converting it to a boolean.

You need to use parentheses, like this:

if not ( tonumber ( rz ) > tonumber ( formula ) ) then 

Thanks

[Castillo]

You're welcome.