Table question

[Markeloff]

Hello,

So, here's my table.

For example, I'm in the first row of the table which index is 0, how to get the next row and its data which is indexed at 1.

local radios = { 
{0,"Radio Off",nil}, 
{1,"Radio 1","link"}, 
{2,"Radio 2","link"}, 
{3,"Radio 3","link"}, 
{4,"Radio 4","link"}, 
{5,"Radio 5","link"}, 
} 

function setCurrentChannel(id) 
if (id < 0) or (id > #radios) then return false; end; 
outputChatBox("setting done") 
channelID = id; 
for i,v in ipairs (radios) do  
if v[1] == id then 
actual = v[2] 
suivant = -- is the v[2] of next row of the table 
previous = -- is the v[2] of previous row of the table 
outputChatBox(v[2]) 
end 
return true; 
end 
end 

[bandi94]

  
  
function setCurrentChannel(id) 
if (id < 0) or (id > #radios) then return false; end; 
outputChatBox("setting done") 
channelID = id; 
for i,v in ipairs (radios) do 
if v[1] == id then 
actual = v[2] 
suivant = v[i+1][2] -- next row data 2 
previous = v[i-1][2] -- prev row data 2 
outputChatBox(v[2]) 
end 
return true; 
end 
end 
  
  

[IIYAMA]

@ bandi94 his code +

  
suivant = v[i+1] and v[i+1][2] or v[1] and v[1][2] -- next row data 2 
previous = v[i-1] and v[i-1][2] or v[#v] and v[#v][2] -- prev row data 2 
  

[Markeloff]

It's solved, thank you guys.