SniperBombix95 Posted September 8, 2013 Share Posted September 8, 2013 Hi guys, I'm here today 'cause i need an "illumination" on this question As the title says, is it possible to create completely new weapons? Because my idea was to (if it's possible) create various weapons like the country rifle but all with different damage, clip size, accuracy, weapon range and sure different models . But I think that cannot be done so easily, i mean weapons works with ids, like 0 , 1, 2 ,32 ecc. and each weapon has an id and a model id. Now my point is how to assign a new id as a weapon and a related model's id. If it's possible, can someone show me a simple script to do that? thanks in advance and i hope in a positive answer. and if i've made some mistake, i'm not english bye SniperBombix Link to comment
50p Posted September 8, 2013 Share Posted September 8, 2013 You cannot create completely new models and have new model IDs. You can replace models and change their properties with setWeaponProperty. Link to comment
SniperBombix95 Posted September 8, 2013 Author Share Posted September 8, 2013 Well ok, i've already used the setWeaponProperties and changed All weapons properties like damage, RoF, range, accuracy, flags ecc. but then i thinked "What about adding more weapons like 3 m4 (m4, m16, scar) ecc. and keep at the same time the original one?" but now you say that it can't be done so... Quick question, what about adding new weapons in the default Gta sa folder? can i add more weapons there? like adding more vehicles, i saw a tutorial on this, but no one on weapons Link to comment
50p Posted September 8, 2013 Share Posted September 8, 2013 Currently, you can't add new models, you can only replace the existing ones. There are some works going on to let scripters/modders add new models, maybe then you'd be able to add new weapons but I doubt it because of the way the weapons system work. So there is only ~40 weapons and that's all we can have. Link to comment
SniperBombix95 Posted September 8, 2013 Author Share Posted September 8, 2013 Ok then, thanks a lot for the answer Link to comment
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