string.find ?

[Dice]

Hi. How are you?

if not string.find(getPlayerName ( getLocalPlayer() ), "[ClanTag]", 1 ) Curious on how to make it more narrow, with this line if someone has the name [Cl it will work. How can i make it so you literally have to have your name as [ClanTag]

[csiguusz]

Since '[' and ']' are 'magical characters', you have to do it so:

string.find(getPlayerName ( getLocalPlayer() ), "%[ClanTag%]", 1 )  

[Dice]

not %[ClanTag]% ?

[csiguusz]

not %[ClanTag]% ?

No.

[Dice]

Didn't work anyways

[Renkon]

string.find(getPlayerName(localPlayer), "\[ClanTag\]") 

[csiguusz]

string.find(getPlayerName(localPlayer), "\[ClanTag\]") 

This was my second thougth, but I tried the first one too, and I think it worked...

[Dice]

ok works thanks, but the problem I was orginally having is let's say a players clantag is RN6 the if someone has the name RN or something, they will be able to pass, I need it to have the whole thing RN6 not just RN or N6

[Guest Guest4401]

Just use the 4th argument plain of string.find to allow "magical" characters...

http://www.lua.org/manual/5.1/manual.ht ... tring.find

E.g:

string.find('[TAG]nameless','[TAG]',1,true) 
--Result: 1   5