Piorun Posted February 24, 2013 Share Posted February 24, 2013 I have one, simple question: Why this code doesn't work? : CLIENT (ucp_c.lua): ucp = {} function ucp.showLoginBar() if guiGetVisible(ucp.loginBar) == false then guiSetVisible(ucp.loginBar, true) else guiSetVisible(ucp.loginBar, false) end end META.XML (ucp): <export function="ucp.showLoginBar" type="client" /> CLIENT (other.lua): call(getResourceFromName("ucp"), "ucp.showLoginBar") and error: failed to call Can anyone help? Link to comment
50p Posted February 24, 2013 Share Posted February 24, 2013 You can't use functions this way. The exported functions must be simply defined as regular functions. function showLoginBar() if guiGetVisible(ucp.loginBar) == false then guiSetVisible(ucp.loginBar, true) else guiSetVisible(ucp.loginBar, false) end end Link to comment
Piorun Posted February 24, 2013 Author Share Posted February 24, 2013 ehh .. crap. Ok thanks. Link to comment
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