Jump to content

isNumeric()


dudeks

Recommended Posts

Posted
function isNumeric(text) 
  if type(text)~="string" and type(text)~="number" then return false end 
  return tonumber(text) and true or false 
end 
  

Posted
age = guiGetText(editage) 
 if isNumeric(age) then 
    .... 
end 

edit:

function isNumeric(text) 
  if type(text)~="string" and type(text)~="number" then return false end 
  return tonumber(text) and true or false 
end 
  

is working. Thanks!

Posted
function isNumeric(text) 
    if type(text) == "string" then 
        text = tostring(text) 
    end 
    return text and true or false 
end 

2mistakes.

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...