مساعده

[Reallife404]

شباب كيف اعمل

dxDrawRectangle

دائري يكون شكله مثل الدائره

[shwaeki]

https://wiki.multitheftauto.com/wiki/DxDrawCircle

[Reallife404]

ممكن شرح اكثر اخ شويكي ؟

[shwaeki]

ادخل على الرابط هاذا هو الكود يلي يساوي دائرة

مثل هاي

https://wiki.multitheftauto.com/wiki/Fi ... xample.png

و الكود هاد انسخة و حطة في ملف كلنت

function dxDrawCircle( posX, posY, radius, width, angleAmount, startAngle, stopAngle, color, postGUI ) 
    if ( type( posX ) ~= "number" ) or ( type( posY ) ~= "number" ) then 
        return false 
    end 
  
    local function clamp( val, lower, upper ) 
        if ( lower > upper ) then lower, upper = upper, lower end 
        return math.max( lower, math.min( upper, val ) ) 
    end 
  
    radius = type( radius ) == "number" and radius or 50 
    width = type( width ) == "number" and width or 5 
    angleAmount = type( angleAmount ) == "number" and angleAmount or 1 
    startAngle = clamp( type( startAngle ) == "number" and startAngle or 0, 0, 360 ) 
    stopAngle = clamp( type( stopAngle ) == "number" and stopAngle or 360, 0, 360 ) 
    color = color or tocolor( 255, 255, 255, 200 ) 
    postGUI = type( postGUI ) == "boolean" and postGUI or false 
  
    if ( stopAngle < startAngle ) then 
        local tempAngle = stopAngle 
        stopAngle = startAngle 
        startAngle = tempAngle 
    end 
  
    for i = startAngle, stopAngle, angleAmount do 
        local startX = math.cos( math.rad( i ) ) * ( radius - width ) 
        local startY = math.sin( math.rad( i ) ) * ( radius - width ) 
        local endX = math.cos( math.rad( i ) ) * ( radius + width ) 
        local endY = math.sin( math.rad( i ) ) * ( radius + width ) 
  
        dxDrawLine( startX + posX, startY + posY, endX + posX, endY + posY, color, width, postGUI ) 
    end 
  
    return true 
end 

و هاد مثال عشين تساوي دائرة

  
addEventHandler( "onClientRender", root,  
    function( ) 
        -- We're starting to draw the circle at 0° which means that the first point of the arc is ( 200+50 | 200 ) 
        -- Therefore the last point is ( 200 | 200+50 ). > Our arc is the "lower right" quarter of the circle. 
        dxDrawCircle( 200, 200, 50, 5, 1, 0, 90 ) 
    end 
)