Table order

[manawydan]

so iam try make this:

local t = {5,nil,2,nil,3} change to this t = {5,2,3}

i try make this but no work

function orderTable(t) 
local nt = {} 
local c = 0 
for k,v in ipairs(t) do 
if(v ~= nil)then 
c = c +1 
print(c) 
table.insert(nt,v) 
end 
end 
return nt 
end 
  
  
addCommandHandler("ta", 
function() 
local t = {5,nil,2,nil,3} 
j = orderTable(t) 
for k,v in ipairs(j)do 
print(tostring(v)) 
end 
end) 

any help?

[Dealman]

Check if the value is nil. If it is, use table.remove.

table.remove(theTable, theIndex); 

[DiSaMe]

'ipairs' iterates up to first nil value. Which means no subsequent values are processed in your code.

[manawydan]

thanks, what I could do? use pairs?

[0xCiBeR]

Yes, the solution is to use pairs as ipairs uses an iterator that only returns pairs of values attributed to numerical keys. This means that they can only return values defined in list format. In addition, if ipairs encounters any nil value, it will stop in its tracks, pairs, on the other hand, iterates through the entire table and returns keys that are non-numerical as well, so that's why you can't use ipairs to do the job.

Hope it helps.

[DiSaMe]

Also, while ipairs starts at key 1 and increases it, pairs loops through the table in unspecified order.

[manawydan]

thanks guys!

[manawydan]

i try make one new code and work

function orderTable(t) 
local nt = {} 
for i=1,#t do 
if(t[i] ~= nil)then 
table.insert(nt,t[i]) 
end 
end 
return nt 
end 

[Buffalo]

# won't return correct items count, because they are not in order

just use your script with pairs

function orderTable(t) 
local nt = {} 
for k,v in pairs(t) do 
table.insert(nt,v) 
end 
return nt 
end