Random files from a folder

[milkshake333]

Hi,

I was wondering if it was possible to find a random file from a folder.

As example, I have 50 .xml files in a folder, and they all have different names.

Is there a function to get the contents of a folder, like files at a certain index, so I could just load a file when I have a number? Like 1-50?

I hope you guys understand this...

Regards,

Rutger Speksnijder.

[#Paper]

So, import all files in the meta.xml, and then in the script:

math.random(1, 50)  

and then u load xml file whit the random number

Edited July 13, 2011 by Guest

[milkshake333]

Yeah okay, but the problem is that if I have to import all the files in the meta.xml, it takes kinda long. 'Cause in this case, it's like 150 files. So I was wondering if there was some sort of function for this.

[#Paper]

Mhh, for open the files in the script i'm not sure that u need to insert these in the meta, u can try like:

xmlLoadFile(":"..getResourceName(getThisResource()).."/"..math.random(1, 150)) 
  

But i'm not sure that works try...

[milkshake333]

That doesn't work, because I said that the files all have a different name, and aren't just numbers.

[#Paper]

That doesn't work, because I said that the files all have a different name, and aren't just numbers.

ah, in that can u have to add in meta

[milkshake333]

Yeah okay, I already thought there was no function for this, though I didn't know for sure. Thanks for the help anyway .

[qaisjp]

Aha, are these xml's being generate by the same resource? In that case, when making an xml file, make a main xml file called master.xml, which specifies all the filenames of the generated ones. Then get the children, then use my function:

  
function table.getr(t, min) 
     return t[math.random(min or 1, table.getn(t))] 
end 

and then get the attributes and or value. But i cant guarantee itll work