exports calling resource

[Dominate]

Hi guys, im asking if i can get name of resource that called a function from another resource.

--- function from resource1
function Func()
	outputChatBox("That function called by: ".. resourceName)  -- print 'That function called by: resource2'
end


--- resource2
exports["resource1"]:Func()

 

[SycroX]

3 minutes ago, Dominate said:

Hi guys, im asking if i can get name of resource that called a function from another resource.

--- function from resource1
function Func()
	outputChatBox("That function called by: ".. resourceName)  -- print 'That function called by: resource2'
end


--- resource2
exports["resource1"]:Func()

 

function testFunction(res)
  outputChatBox("this function called by : "..res, root, 255, 0, 0)
end
------#from another resource
exports["yourResource"]:testFunction(getResourceName(getThisResource()))

you can try this for all your functions

i think that there's no another way

[Dominate]

yeah i know that way but im asking is there's an easy way

maybe there's a way by using debug library

debug

 

[DNL291]

debug.getinfo (https://www.lua.org/pil/23.1.html)

An example:

function a()
	local callingFunction = debug.getinfo(2)
	if callingFunction then
		print(callingFunction.name)
	end
end
function b()
	a()
end
b()

 

EDIT After rereading your message, I realized that I answered it wrong since you meant the resource name and not the function name.

So in this case, you can use the hidden variable "sourceResource", which represents the resource that called the exported function.

--- function from resource1
function Func()
	local callingRes = sourceResource
	if callingRes then
		outputChatBox("That function called by: ".. getResourceName(callingRes))  -- print 'That function called by: resource2'
	end
end

Maybe this is only possible with the call function, I haven't tested it using exports.

Edited April 16, 2018 by DNL291