Tockra Posted July 7, 2010 Share Posted July 7, 2010 Hello guys, i want, that a player with a special clan tag can't connect (ABC). Because this i made a script : http://pastebin.com/Vsn6s6SW There isnt a problem, but i want that a guy, who connects with the Clan tag "abc" cant connect,too because that i made this: http://pastebin.com/AxzgLiJh But that want not run ! Need help... Link to comment
Lordy Posted July 7, 2010 Share Posted July 7, 2010 When you use [] in string functions, it defines a new set http://lua-users.org/wiki/PatternsTutorial look for sets. So when using string.find(stringa,"[abc]") it returns if either a, b or c is found. In order to fix it, you need to escape [ and ]. I think they can be escaped with %[ and %] but I'm not sure. Link to comment
50p Posted July 7, 2010 Share Posted July 7, 2010 string.find looks for patterns. If you don't want it, just turn it off (4th parameter). string.find (s, pattern [, init [, plain]])...A value of true as a fourth, optional argument plain turns off the pattern matching facilities, so the function does a plain "find substring" operation, with no characters in pattern being considered "magic". Note that if plain is given, then init must be given as well. Link to comment
Tockra Posted July 7, 2010 Author Share Posted July 7, 2010 so? : string.find(playerN,"[ABC]",1,false) ? Link to comment
50p Posted July 7, 2010 Share Posted July 7, 2010 Yes. And why don't you try it before you ask? Always try before you ask. Link to comment
Tockra Posted July 7, 2010 Author Share Posted July 7, 2010 Because that dont run ... false is advanced setting... Other question, cant i use getPlayerNametagText for that? €: That run : ..or string.find(playerN,"[abc]",1,true but i dont know why Link to comment
50p Posted July 7, 2010 Share Posted July 7, 2010 Yes, you can, but you should use getPlayerName instead. string.find( getPlayerName( player ), "[abc]", 1, true ); Link to comment
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